(4x^2+23x+25)/(x+4)

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Solution for (4x^2+23x+25)/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(4*x^2+23*x+25)/(x+4) = 0

4*x^2+23*x+25 = 0

4*x^2+23*x+25 = 0

DELTA = 23^2-(4*4*25)

DELTA = 129

DELTA > 0

x = (129^(1/2)-23)/(2*4) or x = (-129^(1/2)-23)/(2*4)

x = (129^(1/2)-23)/8 or x = (-(129^(1/2)+23))/8

(x+(129^(1/2)+23)/8)*(x-((129^(1/2)-23)/8)) = 0

((x+(129^(1/2)+23)/8)*(x-((129^(1/2)-23)/8)))/(x+4) = 0

( x+(129^(1/2)+23)/8 )

x+(129^(1/2)+23)/8 = 0 // - (129^(1/2)+23)/8

x = -((129^(1/2)+23)/8)

( x-((129^(1/2)-23)/8) )

x-((129^(1/2)-23)/8) = 0 // + (129^(1/2)-23)/8

x = (129^(1/2)-23)/8

x in { -((129^(1/2)+23)/8), (129^(1/2)-23)/8 }

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